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Hachima · 10-24-2007, 07:24 PM

the frist keyboard.nextLine() will be ignored when it follows a keyboard.nextInt()

You could request a dummy keyboard.nextLine() to clear the buffer of the newline.

The else if (choice >1 || choice <4 ) statement is incorrect and will always be true.

10-24-2007, 07:24 PM	#2 (permalink)
Hachima Registered User Join Date: Oct 2004 Posts: 1,701	the frist keyboard.nextLine() will be ignored when it follows a keyboard.nextInt() You could request a dummy keyboard.nextLine() to clear the buffer of the newline. The else if (choice >1 \|\| choice <4 ) statement is incorrect and will always be true. Last edited by Hachima : 10-24-2007 at 07:29 PM.